-135t^2-20t+155=0

Solution for -135t^2-20t+155=0 equation:

-135t^2-20t+155=0

a = -135; b = -20; c = +155;
Δ = b2-4ac
Δ = -202-4·(-135)·155
Δ = 84100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{84100}=290$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-290}{2*-135}=\frac{-270}{-270}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+290}{2*-135}=\frac{310}{-270}
=-1+4/27
$